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三道算法1，2簡(jiǎn)單題3、兩個(gè)字符數(shù)S，T，每次可以將S中的一個(gè)移動(dòng)到末尾，最少移動(dòng)多少次使S==T#include <iostream>#include <iterator>#include <map>using namespace std;int main() {string S,T;cin >> S >> T;if(S==T)return 0;int len = S.length();int result =len;map<char,int> S_map{{'a',0},{'b',0},{'c',0},{'d',0},{'e',0},{'f',0},{'g',0},{'h',0},{'i',0},{'j',0},{'k',0},{'l',0},{'m',0},{'n',0},{'o',0},{'p',0},{'q',0},{'r',0},{'s',0},{'t',0},{'u',0},{'v',0},{'w',0},{'x',0},{'y',0},{'z',0}};map<char,int> T_map{{'a',0},{'b',0},{'c',0},{'d',0},{'e',0},{'f',0},{'g',0},{'h',0},{'i',0},{'j',0},{'k',0},{'l',0},{'m',0},{'n',0},{'o',0},{'p',0},{'q',0},{'r',0},{'s',0},{'t',0},{'u',0},{'v',0},{'w',0},{'x',0},{'y',0},{'z',0}};for(int i=0;i<len;i++){S_map[S[i]]+=1;T_map[T[i]]+=1;}for(map<char,int>::iterator itr=S_map.begin();itr!=S_map.end();itr++){if(T_map[itr->first]!=itr->second)return -1;}for(int i=0;i<len;i++){int local=0;local = S.find(T[i]);if(local ==-1)break;else{S.erase(S.begin(),S.begin()+local+1);result-=1;}}cout<<result<<endl;}