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給定兩個(gè)字符串str1和str2，輸出兩個(gè)字符串的最長(zhǎng)公共子序列。如果最長(zhǎng)公共子序列為空，則返回"-1"。目前給出的數(shù)據(jù)，僅僅會(huì)存在一個(gè)最長(zhǎng)的公共子序列 數(shù)據(jù)范圍： 要求：空間復(fù)雜度 ，時(shí)間復(fù)雜度
示例1
輸入
"1A2C3D4B56","B1D23A456A"
輸出
"123456"
示例2
輸入
"abc","def"
輸出
"-1"
示例3
輸入
"abc","abc"
輸出
"abc"
示例4
輸入
"ab",""
輸出
"-1"
加載中...
import java.util.*; public class Solution { /** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請(qǐng)勿修改，直接返回方法規(guī)定的值即可 * * longest common subsequence * @param s1 string字符串 the string * @param s2 string字符串 the string * @return string字符串 */ public String LCS (String s1, String s2) { // write code here } }
class Solution { public: /** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請(qǐng)勿修改，直接返回方法規(guī)定的值即可 * * longest common subsequence * @param s1 string字符串 the string * @param s2 string字符串 the string * @return string字符串 */ string LCS(string s1, string s2) { // write code here } };
#coding:utf-8 # # 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請(qǐng)勿修改，直接返回方法規(guī)定的值即可 # # longest common subsequence # @param s1 string字符串 the string # @param s2 string字符串 the string # @return string字符串 # class Solution: def LCS(self , s1 , s2 ): # write code here
using System; using System.Collections.Generic; class Solution { /** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請(qǐng)勿修改，直接返回方法規(guī)定的值即可 * * longest common subsequence * @param s1 string字符串 the string * @param s2 string字符串 the string * @return string字符串 */ public string LCS (string s1, string s2) { // write code here } }
/** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請(qǐng)勿修改，直接返回方法規(guī)定的值即可 * * longest common subsequence * @param s1 string字符串 the string * @param s2 string字符串 the string * @return string字符串 */ function LCS( s1 , s2 ) { // write code here } module.exports = { LCS : LCS };
<?php /** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請(qǐng)勿修改，直接返回方法規(guī)定的值即可 * * longest common subsequence * @param s1 string字符串 the string * @param s2 string字符串 the string * @return string字符串 */ function LCS( $s1 , $s2 ) { // write code here }
# # 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請(qǐng)勿修改，直接返回方法規(guī)定的值即可 # # longest common subsequence # @param s1 string字符串 the string # @param s2 string字符串 the string # @return string字符串 # class Solution: def LCS(self , s1: str, s2: str) -> str: # write code here
package main import "fmt" /** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請(qǐng)勿修改，直接返回方法規(guī)定的值即可 * * longest common subsequence * @param s1 string字符串 the string * @param s2 string字符串 the string * @return string字符串 */ func LCS( s1 string , s2 string ) string { // write code here }
/** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請(qǐng)勿修改，直接返回方法規(guī)定的值即可 * * longest common subsequence * @param s1 string字符串 the string * @param s2 string字符串 the string * @return string字符串 */ char* LCS(char* s1, char* s2 ) { // write code here }
# # 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請(qǐng)勿修改，直接返回方法規(guī)定的值即可 # # longest common subsequence # @param s1 string字符串 the string # @param s2 string字符串 the string # @return string字符串 # class Solution def LCS(s1, s2) # write code here end end
object Solution { /** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請(qǐng)勿修改，直接返回方法規(guī)定的值即可 * * longest common subsequence * @param s1 string字符串 the string * @param s2 string字符串 the string * @return string字符串 */ def LCS(s1: String,s2: String): String = { // write code here } }
object Solution { /** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請(qǐng)勿修改，直接返回方法規(guī)定的值即可 * * longest common subsequence * @param s1 string字符串 the string * @param s2 string字符串 the string * @return string字符串 */ fun LCS(s1: String,s2: String): String { // write code here } }
import java.util.*; public class Solution { /** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請(qǐng)勿修改，直接返回方法規(guī)定的值即可 * * longest common subsequence * @param s1 string字符串 the string * @param s2 string字符串 the string * @return string字符串 */ public String LCS (String s1, String s2) { // write code here } }
/** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請(qǐng)勿修改，直接返回方法規(guī)定的值即可 * * longest common subsequence * @param s1 string字符串 the string * @param s2 string字符串 the string * @return string字符串 */ export function LCS(s1: string, s2: string): string { // write code here }
public class Solution { /** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請(qǐng)勿修改，直接返回方法規(guī)定的值即可 * * longest common subsequence * @param s1 string字符串 the string * @param s2 string字符串 the string * @return string字符串 */ func LCS ( _ s1: String, _ s2: String) -> String { // write code here } }
struct Solution{ } impl Solution { fn new() -> Self { Solution{} } /** * 代碼中的類名、方法名、參數(shù)名已經(jīng)指定，請(qǐng)勿修改，直接返回方法規(guī)定的值即可 * * longest common subsequence * @param s1 string字符串 the string * @param s2 string字符串 the string * @return string字符串 */ pub fn LCS(&self, s1: String, s2: String) -> String { // write code here } }
"1A2C3D4B56","B1D23A456A"
"123456"
"abc","def"
"-1"
"abc","abc"
"abc"
"ab",""
"-1"